Resources:
Step 1.
SELECT * FROM customers;
Step 2.
SELECT * FROM orders;
Step 3.
SELECT * FROM products ORDER BY Price DESC;
Step 4.
SELECT customerName, COUNT(*) AS 'number of orders' FROM customers INNER JOIN orders ON orders.customerID = customers.customerID GROUP BY customers.customerID;
Note: Step 4 will give you errors if you're using firefox or any other browser other than Chrome, Safari, or Opera. This is because the SQL Try-It Editor is using WebSQL. See here for further discussion of errors that could occur when using firefox.